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Anyone good with Regex or filebot |
| Posted: 02 May 2022 07:55 | |||
Posts: 32 Joined: 2020-06-25 | Hi All, So with the latest update for SportScanner, it is working wonderfully for me so big thanks to everyone involved. Next is there anyone who knows they way around filebot for the naming conversions? or experts with Regex I posted in the filebot forum but got the use the plain text with no explanation on how to do it, so thought someone here might be better equipped to handle such a request. I have been looking at ways to take parts of the file name and make a new one that will work with The Sports DB this is one example EPL 2009 Aston Villa vs Wigan 08 14 720pEN60fps WhAma.mp4 this is the file I have and I need to extract certain bits from the file name and discard the rest to make it look like this English.Premier.League.2009-08-14.Aston.Villa.vs.Wigan So EPL - English.Premier.League 2009 - 2009-08-14 Aston Villa - Aston.Villa Wigan - Wigan 702p onwards get deleted. Is there a way to do it? basically I am looking at splitting the file name (EPL) (2009) (Aston Villa) vs (Wigan) (08) (14) (720pEN60fps) (WhAma).mp4 so the spaces will be the bookmarks for isolatation I am no coder of programmer but what I see is possibility in a formula First we find all numbers involved so 2009, 08,14,720,60 next find if there is 720 and remove everything up till the extension from there next the remaining numbers assigned tags 2009 -(a) 08 - (b) 14 - (c) next the strings left EPL (d) name before vs replace space with(.) - (e) name after vs replace space with(.) - (f) now put it together (d).(a)-(b)-(c).(e).vs.(f).ext In my head it seems simple but in actual real life lol is best to aske some one who understands regex type problems. Any advice in doing this will be greatly appreciated . Thanks | ||
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| Posted: 03 May 2022 00:57 | |||
Posts: 4 Joined: 2022-05-03 | What language are you using? If PHP, I would use this approach: // Original string. $str = 'EPL 2009 Aston Villa vs Wigan 08 14 720pEN60fps WhAma.mp4'; // Get the primary substring. preg_match_all( '/^(.*)(?= 720)/', $str, $matches ); $str = $matches[1][0]; // EPL 2009 Aston Villa vs Wigan 08 14 // Format the date. preg_match_all( '/\s\d{2,4}/', $str, $parts ); $parts = array_map( 'trim', $parts[0] ); // array( '2009', '08', '14' ) $date = sprintf( '%1$s-%2$s-%3$s', $parts[0], $parts[1], $parts[2] ); // 2009-08-14 // Remove date $parts from original string. $str = preg_replace( '/\s\d{2,4}/', '', $str ); // EPL Aston Villa vs Wigan // Replace all whitespaces with a dot (.). $str = preg_replace( '/\s/', '.', $str ); // Replace `EPL` with `English.Premier.League.$date`. $str = preg_replace( '/EPL/', sprintf( 'English.Premier.League.%s', $date ), $str ); echo $str; // English.Premier.League.2009-08-14.Aston.Villa.vs.Wigan The whole solution can be viewed online here: https://sandbox.onlinephpfunctions.com/c/47a3a zag | ||
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| Posted: 03 May 2022 06:10 | |||
Posts: 32 Joined: 2020-06-25 | Wow that is exactly what I was looking to do. Thank you very much. I thought my idea would only live in my head lol. Now to implement it in the EPL directory and do it to each new file transferred there. Thank you once again daveyjake | ||
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| Posted: 05 May 2022 19:56 | |||
 zag Posts: 3,331 Joined: 2020-03-23 | Awesome, thanks for the help | ||
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